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Oct 12, 2020 at 5:03 history edited Iosif Pinelis CC BY-SA 4.0
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Oct 12, 2020 at 4:20 comment added Iosif Pinelis @opfromthestart : So that not to waste the time and effort of people who try their best to help you, I do think you should make your post as clear as possible from the very beginning, with all exceptions and all quantifiers (such as "for all real $x\ne1$") in place, and without using statements such as "those cannot intersect outside of a contradiction", to which it seems impossible to attach a meaning.
Oct 12, 2020 at 4:13 comment added opfromthestart What other points would the function be in contradiction at?
Oct 12, 2020 at 4:06 comment added opfromthestart Yes, I am aware of this, I should have included it in my original post. I want a value of 0 for either x or y to mean that it is certain that the value is 0, while a value of 1 for x or y means that it is certain it is 1. Since those cannot intersect outside of a contradiction, it would not matter for my application. It is almost desirable that it be undefined at f(0,1)
Oct 12, 2020 at 3:20 history edited Iosif Pinelis CC BY-SA 4.0
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Oct 12, 2020 at 0:35 comment added user44191 That said, $(0, 1)$ and $(1, 0)$ (and surrounding neighborhoods) should be the only problems.
Oct 11, 2020 at 21:26 history answered Iosif Pinelis CC BY-SA 4.0