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S Dec 6, 2021 at 22:30 history bounty ended Noah Schweber
S Dec 6, 2021 at 22:30 history notice removed Noah Schweber
Dec 3, 2021 at 20:41 vote accept Noah Schweber
Dec 3, 2021 at 16:24 history edited Noah Schweber CC BY-SA 4.0
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Dec 3, 2021 at 16:23 comment added Noah Schweber @FedorPakhomov Yes I forgot to include that - note that the restriction to infinite models shows up implicitly in my claim that "projective infinitary = second-order" (without an infinite domain to work with this doesn't hold). Fixed, thanks!
Dec 3, 2021 at 12:46 answer added Fedor Pakhomov timeline score: 7
Dec 3, 2021 at 11:45 comment added Fedor Pakhomov The answer is no for fairly boring reason. Reasoning in $\mathsf{ZFC}+V=L$ consider some set $C$ of finite models in the signature of pure equality such that for no second-order sentence $\varphi$ we have $M\models \varphi\iff M \in C$ ($C$ exists by cardinality argument). Since validity of second-order sentences in finite models isn't changed by forcing any $\mathcal{L}_{\omega_1,\omega}$-formula $\psi$ axiomatizing $C$ gives a counterexample. I guess the right question should be about infinite models.
Dec 2, 2021 at 21:13 history edited Noah Schweber CC BY-SA 4.0
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Dec 2, 2021 at 20:51 history edited Noah Schweber CC BY-SA 4.0
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S Dec 2, 2021 at 20:51 history bounty started Noah Schweber
S Dec 2, 2021 at 20:51 history notice added Noah Schweber Draw attention
S Oct 31, 2020 at 6:06 history bounty ended CommunityBot
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Oct 23, 2020 at 4:44 history edited Noah Schweber CC BY-SA 4.0
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S Oct 23, 2020 at 4:17 history bounty started Noah Schweber
S Oct 23, 2020 at 4:17 history notice added Noah Schweber Draw attention
Oct 10, 2020 at 21:37 history asked Noah Schweber CC BY-SA 4.0