Timeline for Advanced view of the napkin ring problem?
Current License: CC BY-SA 2.5
5 events
| when toggle format | what | by | license | comment | |
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| Sep 5, 2010 at 20:09 | comment | added | Aaron Meyerowitz | I think I might have seen it in vol 1 of Mathematics and Plausible reasoning by George Polya. A similar result holds for paraboloids and other conics as I recall. I suppose a cone is easy (given the cylinder) since it has the same volume as the cylinder meeting its equator. | |
| Sep 5, 2010 at 0:52 | comment | added | Michael Hardy | I'm going to have to think about this one..... If this works, it seems to me that essentially the same reasoning could work for other geometric problems, even though I don't know right now what those would be. | |
| Sep 1, 2010 at 14:56 | history | edited | Aaron Meyerowitz | CC BY-SA 2.5 |
same idea, simplified
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| Sep 1, 2010 at 8:03 | history | edited | Aaron Meyerowitz | CC BY-SA 2.5 |
spelling
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| Sep 1, 2010 at 7:44 | history | answered | Aaron Meyerowitz | CC BY-SA 2.5 |