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Nov 2, 2020 at 19:59 comment added diverietti @wnx I was (and am) totally calm! My tone wasn't aggressive, maybe I had to add some emoticon? :) This said, the OPs question lacks a lot of information and has indeed some mistakes in it! It is indeed quite indecipherable. But it's not a big deal, right? I was just trying to push the OPs to reformulate better his question, for his own advantage!
Oct 3, 2020 at 19:33 comment added diverietti @Samir, thai is as wrong as possibile, in general! Once again you should write better your original question! What do you have in mind? A projective manifold? Or merely a compact complex one?
Oct 2, 2020 at 16:07 vote accept Samir
Oct 2, 2020 at 16:03 comment added Samir @diverietti I think that if $ K_X $ is not nef, then $ \mathcal {k} (X) = - \infty $ where $ \mathcal {k} (X) $ is the Kodaira dimension
Oct 2, 2020 at 14:39 history edited diverietti CC BY-SA 4.0
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Oct 2, 2020 at 14:37 comment added abx @diverietti: Yes, of course I had the projective case in mind. And I don't understand either...
Oct 2, 2020 at 14:30 answer added diverietti timeline score: 5
Oct 2, 2020 at 13:38 comment added diverietti In any case I really don't understand what the OP would like to know...
Oct 2, 2020 at 13:35 comment added diverietti @abx what you say it's ok for projective manifolds. But this is merely compact complex. Even in the compact Kähler case "$K_X$ not nef implies presence of rational curves" is not known!
Oct 2, 2020 at 13:13 comment added abx @diverietti: if $X$ is not minimal it contains some rational curve, which lifts to the universal covering.
Oct 2, 2020 at 12:55 comment added diverietti @abx thanks. But still, I don't immediately see why if $X$ satisfies 1) and 2), then this is true...
Oct 2, 2020 at 12:45 review Close votes
Oct 8, 2020 at 3:04
Oct 2, 2020 at 12:29 comment added abx I suspect the OP claims this only for $X$ satisfying 1) and 2). But the question certainly needs to be clarified.
Oct 2, 2020 at 12:21 comment added diverietti $K_X$ big does NOT imply $K_X$ nef, nor in general neither in this case.
Oct 2, 2020 at 10:41 history asked Samir CC BY-SA 4.0