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Oct 2, 2020 at 17:21 history became hot network question
Oct 2, 2020 at 15:08 vote accept M. Winter
Oct 2, 2020 at 12:36 answer added Moritz Firsching timeline score: 23
Oct 2, 2020 at 10:50 comment added HJRW I see it now! The straight line between two vertices of the underlying tetrahedron passes "below" the straight line between the vertices in the middle of the faces of the tetrahedron, so the convex hull contains additional edges and vertices. Thanks for the explanation.
Oct 2, 2020 at 10:46 comment added M. Winter @HJRW The picture shows a spherical polyhedron rather than a convex one (it is not the convex hull of finitely many points, has not only flat faces, etc.). The fact that the triakis tetrahedron is not inscribable can be found e.g. in "Six Topics on Inscribable Polytopes" by Padrol and Ziegler (p. 409 in "Advances in Discrete Differential Geometry").
Oct 2, 2020 at 10:42 comment added HJRW Could you give a bit more detail about your reference to the triakis tetrahedron? The page you link to seems to include a picture of an inscription of the triakis tetrahedron on a sphere: en.wikipedia.org/wiki/Triakis_tetrahedron#/media/… . What am I missing?
Oct 2, 2020 at 9:40 history edited M. Winter CC BY-SA 4.0
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Oct 2, 2020 at 9:15 history asked M. Winter CC BY-SA 4.0