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Sep 30, 2020 at 15:52 comment added Simon Perhaps it doesn't have a (very known) name and "absolute value of a discrete triangular random variable" is good enough. Thank you all anyway. :)
Sep 29, 2020 at 9:15 comment added Jeppe Stig Nielsen The random variable $I-J$ could be called "discrete triangular"; it is centered at zero. But the poster asks for the absolute value of that, namely $Z=|I-J|$.
Sep 28, 2020 at 20:28 comment added user44143 This is not a discrete triangular distribution, since the probability that the difference is 0 is roughly half the probability that it is 1.
Sep 28, 2020 at 19:51 comment added Simon Thanks @CarloBeenakker. I see how that distribution is similar, but I don't exactly understand how you would discretize it to yield the distribution I calculated...
S Sep 28, 2020 at 19:42 history suggested RobPratt
added a tag
Sep 28, 2020 at 19:35 review Suggested edits
S Sep 28, 2020 at 19:42
Sep 28, 2020 at 18:27 comment added Carlo Beenakker this is called a triangular distribution
Sep 28, 2020 at 18:02 review First posts
Sep 28, 2020 at 18:49
Sep 28, 2020 at 17:59 history asked Simon CC BY-SA 4.0