Timeline for Resonance arising when harmonic oscillator is excited using sawtooth
Current License: CC BY-SA 4.0
13 events
when toggle format | what | by | license | comment | |
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S Sep 27, 2020 at 15:24 | history | suggested | gmvh |
added "mp.mathematical-physics" as alternative top-level tag
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Sep 27, 2020 at 13:55 | review | Suggested edits | |||
S Sep 27, 2020 at 15:24 | |||||
Sep 20, 2020 at 22:22 | comment | added | John D. Cook | The kick argument makes sense. However, it would imply that you always get resonance, regardless of the driving frequency, but you only get resonance for special frequencies. | |
Sep 20, 2020 at 19:42 | comment | added | Massimo Ortolano | This question shows why mathematicians should take more engineering classes ;-) | |
Sep 20, 2020 at 18:53 | comment | added | alephzero | It is easy (for a physicist/engineer!) to see why physically. The discontinuity in the sawtooth function gives the oscillator a "kick". Since there is no damping in the system, it resonates just as well if you "kick" it once every $n$ cycles of its natural frequency of vibration.as if you "kick" it at every cycle. | |
Sep 20, 2020 at 15:51 | history | edited | Rodrigo de Azevedo | CC BY-SA 4.0 |
edited title
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Sep 20, 2020 at 13:58 | history | edited | Rodrigo de Azevedo | CC BY-SA 4.0 |
edited title
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Sep 20, 2020 at 2:34 | history | became hot network question | |||
Sep 19, 2020 at 18:58 | vote | accept | John D. Cook | ||
Sep 19, 2020 at 18:49 | answer | added | gmvh | timeline score: 18 | |
Sep 19, 2020 at 18:42 | comment | added | gmvh | Doesn't this follow from the Fourier decomposition of the sawtooth function? | |
Sep 19, 2020 at 18:41 | history | edited | user44143 | CC BY-SA 4.0 |
top-level tag and more descriptive title
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Sep 19, 2020 at 18:33 | history | asked | John D. Cook | CC BY-SA 4.0 |