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Sep 18, 2020 at 10:18 vote accept Anonymous
Sep 18, 2020 at 9:01 answer added Simon Wadsley timeline score: 4
Sep 18, 2020 at 8:26 comment added Anonymous That map is not surjective is it? What would map to the coset $1+I$? I was thinking about using free rings as well, but couldn't think of a way to make it work. Maybe there's a way though.
Sep 18, 2020 at 7:23 comment added user130903 How about taking the ring freely generated by two non-commuting variables $X$ and $Y$. Set $I=RX$. Then the annihilator is zero and the map $w\mapsto wY$ is an isomorphism form $R$ to $R/I$.
Sep 18, 2020 at 4:43 history asked Anonymous CC BY-SA 4.0