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Sep 14, 2020 at 14:12 comment added Iosif Pinelis @AsafShachar : I did miss that term. However, now the solution is only a bit simpler. I have also added details.
Sep 14, 2020 at 14:10 history edited Iosif Pinelis CC BY-SA 4.0
added 76 characters in body
Sep 14, 2020 at 7:46 comment added Asaf Shachar This seems like a nice solution, thanks. I am sorry to bother you, but if I am not mistaken, the rewriting of the equation should be $G(r,y):=2^r y^{2 r-1} (r+y-ry)-1=0, $ instead of $G(r,y):=2^r y^{2 r-1} (r+y)-1=0. $ (you have a missing term of $ry$ coming from the multiplication of the original equation by $\sqrt s=1-y$). I was able to verify all the steps after this modification, except for the last one which concerns the sign of $G'_r$.
Sep 13, 2020 at 17:00 history edited Iosif Pinelis CC BY-SA 4.0
added 67 characters in body
Sep 13, 2020 at 15:58 history answered Iosif Pinelis CC BY-SA 4.0