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Sep 13, 2020 at 20:06 comment added Asaf Karagila @Andreas: That's a good point. If $\Bbb R$ can be well-ordered, but some strange sets exist above it, it would be a counterexample. I suppose that the right question, then, is restricting these choice principles to sets of reals.
Sep 13, 2020 at 14:24 history became hot network question
Sep 13, 2020 at 13:42 answer added Martin Väth timeline score: 1
Sep 13, 2020 at 12:41 comment added Andreas Blass Since (UMM) is only about Polish spaces, it should be preserved from the ground model to symmetric extensions that introduce no new sets of low rank. So I'd be inclined to try violating (UCC) among sets of very high rank and thus answer Problem 2 negatively.
Sep 13, 2020 at 8:48 comment added Asaf Karagila @bof: I can't say if the answer is positive or not, but at least in Truss' model, the countable union of countable sets of reals is countable, but $\omega_1$ is singular.
Sep 13, 2020 at 8:39 history edited YCor
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Sep 13, 2020 at 7:26 comment added bof And what about (UCM), the union of a countable family of countable sets is meager? Does (UCM) imply (UCC)?
Sep 13, 2020 at 7:01 comment added Asaf Karagila Good questions.
Sep 13, 2020 at 6:57 history edited Taras Banakh CC BY-SA 4.0
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Sep 13, 2020 at 6:24 history asked Taras Banakh CC BY-SA 4.0