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Sep 14, 2020 at 17:02 history edited Ben Ciotti CC BY-SA 4.0
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Sep 13, 2020 at 3:19 history became hot network question
Sep 12, 2020 at 22:31 answer added Pietro Majer timeline score: 7
Sep 12, 2020 at 21:02 comment added Ben Ciotti @PietroMajer Your first definition. Thank you for pointing that out. I have edited the post to make it more clear.
Sep 12, 2020 at 21:01 history edited Ben Ciotti CC BY-SA 4.0
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Sep 12, 2020 at 19:57 comment added Pietro Majer In the definition of $C^1_0$, do you mean: (i) continuously differentiable on $\Omega$, continuous on $\overline \Omega$, vanishing on $\partial \Omega$, or (ii) : continuously differentiable on $\overline \Omega$, and vanishing on $\partial \Omega$. For instance : if $\Omega$ is the unit ball, and $f(x)=\sqrt{1-\|x\|^2}$, does $f\in C^1_0$ ?
Sep 12, 2020 at 19:25 history edited Ben Ciotti CC BY-SA 4.0
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Sep 12, 2020 at 19:14 history asked Ben Ciotti CC BY-SA 4.0