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Sep 14, 2020 at 16:38 comment added Bunyamin Sari You also want to ask copies of $\ell^n_p$'s as blocks in the space, otherwise you can always find them in $\ell_1$ for $p\le 2$.
Sep 14, 2020 at 16:30 comment added Bunyamin Sari You need to be more specific. It is trivial to give counterexample to this. Take $\ell_1$-sum of $\ell^n_p$'s, $\left(\sum_n \ell^n_p\right)_{\ell_1}$
Sep 14, 2020 at 5:18 comment added JWP_HTX Thanks for your helpful answer! As it happens, I am interested in Banach spaces that are known to admit $\ell_{1}$ as a unique spreading model and that (I believe) cannot contain $\ell_{p}^{n}$'s.
Sep 13, 2020 at 14:58 vote accept JWP_HTX
Sep 12, 2020 at 13:52 history answered Bunyamin Sari CC BY-SA 4.0