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Aug 30, 2010 at 11:11 comment added HenrikRüping If one wants to get rid off the $\approx$ sign, one could also just take $A_1$ as above and $A_2:=cH((0,0),(2,-2),(2,2))$
Aug 30, 2010 at 10:35 vote accept HenrikRüping
Aug 30, 2010 at 10:18 history edited Sergei Ivanov CC BY-SA 2.5
minor corrections
Aug 30, 2010 at 9:56 comment added HenrikRüping In my figure the marked points are the vertices of a trapezoid instead of a rectangle. But still its midpoint is the midpoint of $S_2$, I think.
Aug 30, 2010 at 9:29 history answered Sergei Ivanov CC BY-SA 2.5