Timeline for Smooth covers pulling back a cohomology class to any algebraic multiple
Current License: CC BY-SA 4.0
12 events
| when toggle format | what | by | license | comment | |
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| Sep 8, 2020 at 23:08 | history | became hot network question | |||
| Sep 8, 2020 at 17:18 | history | edited | user164740 | CC BY-SA 4.0 |
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| Sep 8, 2020 at 16:17 | vote | accept | CommunityBot | ||
| Sep 8, 2020 at 15:56 | answer | added | Phil Tosteson | timeline score: 7 | |
| Sep 8, 2020 at 15:27 | history | edited | user164740 |
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| Sep 8, 2020 at 15:19 | comment | added | user164740 | @PhilTosteson thank your for your remark | |
| Sep 8, 2020 at 15:19 | history | edited | user164740 | CC BY-SA 4.0 |
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| Sep 8, 2020 at 15:18 | comment | added | Phil Tosteson | This means that $x$ is an eigenvalue of a matrix with integer entries, hence an algebraic integer. | |
| Sep 8, 2020 at 15:17 | comment | added | user164740 | @MarkGrant it's $M\to M$ | |
| Sep 8, 2020 at 15:16 | comment | added | Michael Albanese | @MarkGrant: In the latter case, the equation $\phi^*\rho = x\rho$ doesn't make sense. | |
| Sep 8, 2020 at 15:15 | comment | added | Mark Grant | Did you really mean to ask about covering maps $M\to M$, or covering maps $\widetilde M\to M$? I strongly suspect the answer is negative in the former case; in the latter I'm not so sure. | |
| Sep 8, 2020 at 15:07 | history | asked | user164740 | CC BY-SA 4.0 |