Timeline for On the equation $x^3 + y^3 = z^4$
Current License: CC BY-SA 4.0
5 events
| when toggle format | what | by | license | comment | |
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| Sep 7, 2020 at 19:12 | comment | added | Joe Silverman | Note that this parametrization doesn't only find infinitely many rational solutions, it actually finds all solutions. Here's why. It obviously gives $(0,0,0)$ by taking $s=t=0$. Now suppose that $(x,y,z)$ is a solution with $xyz\ne0$. Then take $s=x/z$ and $t=y/z$, and you'll get an $(s,t)$ pair such that when you plug them into Nullhomologous' formulas, you get back the original $(x,y,z)$. | |
| Sep 7, 2020 at 18:08 | comment | added | user123305 | But how did you arrive at your answer ? May you also see mathoverflow.net/q/371113/123305, | |
| Sep 7, 2020 at 14:24 | comment | added | user123305 | Thanks ! Any other parametrization besides yours ? | |
| Sep 7, 2020 at 14:19 | vote | accept | CommunityBot | ||
| Sep 7, 2020 at 14:15 | history | answered | Nulhomologous | CC BY-SA 4.0 |