Timeline for Concerning the Galois resolvent
Current License: CC BY-SA 4.0
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Aug 31, 2020 at 2:01 | comment | added | Asvin | So $S_n$ acts on the $\tau^\sigma$ and the Galois group $G$ itself acts by it's embedding into $S_n$. The $G(T)$ should be a product of $(T-g\tau)$ for $g \in G$ and the other polynomials will correspond to the other orbits of $G$ on the set of $\tau^\sigma$. As such they will all be of the same degree. They have to be pairwise different because their roots of different! | |
Aug 31, 2020 at 1:24 | history | edited | MathCrawler | CC BY-SA 4.0 |
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Aug 30, 2020 at 23:01 | history | edited | MathCrawler | CC BY-SA 4.0 |
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Aug 30, 2020 at 22:54 | history | asked | MathCrawler | CC BY-SA 4.0 |