Skip to main content
11 events
when toggle format what by license comment
Aug 29, 2020 at 15:35 vote accept Johnny T.
Aug 29, 2020 at 5:00 comment added fedja Better upper bound on the deviation from the area? Certainly not: if you move $\beta$ and $\gamma$ by almost $1$ from some integer plus epsilon to the next integer minus epsilon, the number of integer points does not change but the area changes pretty much by the sum of the sides that is your current bound. Perhaps you wanted to ask something else or I misunderstood the question?
Aug 28, 2020 at 17:31 comment added Fedor Petrov The question reduces to estimates of the sums $\sum_{k=1}^n \{\gamma k\}$. For fixed irrational $\gamma$ and large $n$ this is about $n/2$.
Aug 28, 2020 at 14:20 answer added Iosif Pinelis timeline score: 5
Aug 28, 2020 at 11:59 comment added Stanley Yao Xiao In general I don't think you can do much better. Consider the triangle with end points $(1,1), (n,1), (n,(n+1)/n), n \in \mathbb{N}$ for example. The area is equal to $1/2$, but there are $n$ integral points on the boundary. This is essentially the worst case though.
S Aug 28, 2020 at 11:28 history edited Johnny T.
retagging the question
S Aug 28, 2020 at 11:28 history suggested vidyarthi CC BY-SA 4.0
retagging the question
Aug 28, 2020 at 9:44 review Suggested edits
S Aug 28, 2020 at 11:28
Aug 28, 2020 at 8:31 history edited Johnny T. CC BY-SA 4.0
added 2 characters in body
Aug 28, 2020 at 7:57 history edited Johnny T. CC BY-SA 4.0
added 22 characters in body
Aug 28, 2020 at 7:52 history asked Johnny T. CC BY-SA 4.0