Skip to main content
13 events
when toggle format what by license comment
Sep 1, 2020 at 21:39 comment added guest0803 In addition to @Hacon's comment, in [loc. cit. \S 3] Koll\'ar has also pinpointed the torsion free and the torsion part of $R^if_*\mathcal{O}_X$. The torsion free part is the dual of $R^{n-i}f_*\omega_X$ and hence is also reflexive.
Aug 29, 2020 at 2:21 comment added xin fu @Hacon. Thanks for the comment!
Aug 28, 2020 at 15:23 comment added Hacon If you strengthen your smoothness conditions, then it is true. Assume that $f$ is is smooth over $U=Y-B$ the complement of a snc divisor. Then $Rf_*\omega _X=\sum R^if_*\omega _X[-i]$ and each $R^if_*\omega _X$ and $R^if_*\mathcal O _X$ is locally free (Koll\'ar's Higher Direct Images II Thm 2.6). Note that the $R^if_*\omega _X$ are always torsion free.
S Aug 27, 2020 at 22:56 history suggested KReiser CC BY-SA 4.0
dim changed to \dim
Aug 27, 2020 at 22:24 review Suggested edits
S Aug 27, 2020 at 22:56
Aug 27, 2020 at 20:16 history edited xin fu CC BY-SA 4.0
deleted 280 characters in body
Aug 27, 2020 at 20:10 history edited xin fu CC BY-SA 4.0
added 11 characters in body
Aug 27, 2020 at 20:03 comment added xin fu @Anonymous Nice example, thanks!
Aug 27, 2020 at 19:58 comment added Anonymous Q1: Take a normal surface $Y'$ with non-rational singularity. Let $g:X \to Y'$ be a resolution, and let $f:X \to Y = \mathbf{P}^2$ be the composition of $g$ with a finite map $Y' \to \mathbf{P}^2$. Then $R^1 f_* \mathcal{O}_X \neq 0$ and is supported at finitely many points.
Aug 27, 2020 at 19:45 history edited xin fu CC BY-SA 4.0
added 11 characters in body
Aug 27, 2020 at 19:42 comment added xin fu @abx Thanks.Yes I need $f$ surjective.
Aug 27, 2020 at 19:18 comment added abx As your questions stand, the answer is no for obvious reasons: just take for $f$ a closed immersion. You probably want $f$ surjective, $X$ connected, ...?
Aug 27, 2020 at 19:01 history asked xin fu CC BY-SA 4.0