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May 28, 2021 at 8:06 comment added user122276 @StefanKohl - when you turn something into a comment - can you include the entire message? If you look at the other answer you will observe that he is trying to answer a question that is not correctly phrased. He has not observed that the asker is using the wrong definition of a "morphism".
May 27, 2021 at 13:23 comment added user122276 Question: "Definition: (Lie Pseudoalgebra) A Lie pseudoalgebra consists of a commutative algebra $\mathcal{A}$ and a Lie algebra $\mathfrak{g}$, such that $\mathfrak{g}$ is an $\mathcal{A}$-module and $\mathcal{A}$ acts on $\mathfrak{g}$ by derivations, i.e. we have a Lie algebra morphism $\rho \colon \mathfrak{g} \to \mathrm{Der}(\mathcal{A})$ which is also an $\mathcal{A}$-module morphism and we have $$ [\xi_1, a \xi_2] = a[\xi_1,\xi_2] + \rho(\xi_1)(a)\xi_2$$ for $\xi_1, \xi_2 \in \mathfrak{g}$, $a \in \mathcal{A}$." Comment: If $k \rightarrow B \xrightarrow f A$ is a map of c
May 27, 2021 at 13:05 history bumped CommunityBot This question has answers that may be good or bad; the system has marked it active so that they can be reviewed.
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Aug 30, 2020 at 8:40 answer added Gerrit Begher timeline score: 0
Aug 25, 2020 at 12:48 history edited YCor CC BY-SA 4.0
removed capitals
Aug 25, 2020 at 12:35 history asked Marvin Dippell CC BY-SA 4.0