Timeline for Finding the asymptotic of the function $\Lambda(x):=\sum_{1 \leq m,n \leq x \,\land \,\gcd(m,n)=1} \frac{1}{mn}$

11 events

when toggle format	what		by	license	comment
Feb 1, 2021 at 9:25	comment	added	GH from MO		@AlexeyUstinov: Indeed, since $\sum_{k=1}^\infty\mu(k)\log^2 k/k^2$ converges.
Feb 1, 2021 at 8:59	comment	added	Alexey Ustinov		One can also replace the first $O(1)$ by $O(k\log x/x).$ It will give the constant term in asymptotic formula and the error term $O(\log^2 x/x).$
Aug 23, 2020 at 3:31	vote	accept	Alapan Das
Aug 20, 2020 at 10:57	history	edited	GH from MO	CC BY-SA 4.0	added 2 characters in body
Aug 20, 2020 at 10:48	history	edited	GH from MO	CC BY-SA 4.0	added 289 characters in body
Aug 20, 2020 at 10:19	history	edited	GH from MO	CC BY-SA 4.0	added 168 characters in body
Aug 20, 2020 at 4:05	history	edited	GH from MO	CC BY-SA 4.0	added 9 characters in body
Aug 20, 2020 at 4:04	vote	accept	Alapan Das
Aug 23, 2020 at 3:31
Aug 20, 2020 at 4:03	history	edited	GH from MO	CC BY-SA 4.0	added 16 characters in body
Aug 20, 2020 at 3:57	history	edited	GH from MO	CC BY-SA 4.0	added 147 characters in body
Aug 20, 2020 at 3:31	history	answered	GH from MO	CC BY-SA 4.0