Timeline for Asymptotics of $\chi_m$-distribution where the degree of freedom $m \to \infty?$
Current License: CC BY-SA 4.0
10 events
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| Sep 10, 2020 at 15:17 | comment | added | Henry | Learning math: you are correct but I cannot edit comments. I should have written $\dfrac{\chi_m -\sqrt{m-1/2}}{\sqrt{1/2}}$ converges in distribution to a standard normal distribution $\mathcal N(0,1) $ as $m$ increases | |
| Sep 10, 2020 at 14:50 | comment | added | Learning math | @Henry BTW: a little typo I think: your denominator would be $1/\sqrt{2}$, not $1/2.$ | |
| Aug 21, 2020 at 10:25 | comment | added | Learning math | @Henry Thanks for pointing this out - this is indeed of help here - appreciate it! | |
| Aug 21, 2020 at 10:20 | history | edited | Learning math | CC BY-SA 4.0 |
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| Aug 20, 2020 at 18:26 | vote | accept | Learning math | ||
| Aug 20, 2020 at 14:40 | comment | added | Henry | Related: stats.stackexchange.com/questions/241504/… which (since $\chi^2_1$ has a mean of $1$ and variance of $2$) implies $\dfrac{\chi_m -\sqrt{m-1/2}}{1/2}$ converges in distribution to a standard normal distribution $\mathcal N(0,1)$ as $m$ increases, the same result as you attribute to Fisher | |
| Aug 19, 2020 at 21:26 | history | edited | Learning math | CC BY-SA 4.0 |
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| Aug 19, 2020 at 21:22 | answer | added | Iosif Pinelis | timeline score: 2 | |
| Aug 19, 2020 at 21:10 | history | edited | Learning math | CC BY-SA 4.0 |
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| Aug 19, 2020 at 20:58 | history | asked | Learning math | CC BY-SA 4.0 |