Timeline for Bredon cohomology of a permutation action on $S^3$
Current License: CC BY-SA 4.0
5 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Aug 17, 2020 at 10:24 | vote | accept | Grisha Taroyan | ||
| Aug 17, 2020 at 7:22 | vote | accept | Grisha Taroyan | ||
| Aug 17, 2020 at 8:14 | |||||
| Aug 16, 2020 at 23:04 | answer | added | Steve Costenoble | timeline score: 3 | |
| Aug 16, 2020 at 15:26 | comment | added | Tyler Lawson | I think you're correct. $\underline{\Bbb Z}$ coefficients have the property that they compute the integral cohomology of the orbit space $S^3 / (\Bbb Z/2)$, and by a slightly different cell decomposition I think this space is homotopy equivalent to $S^3$. | |
| Aug 16, 2020 at 12:48 | history | asked | Grisha Taroyan | CC BY-SA 4.0 |