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Aug 17, 2020 at 17:10 vote accept joro
Aug 17, 2020 at 16:45 comment added Sam Hopkins @joro: IIRC you can't delete a question that has an answer with positive score (nor should you!).
Aug 17, 2020 at 15:59 comment added joro This question is entirely wrong because of program bug (very likely in upstream sage). Sorry about wasting your time. Probably will delete the question.
Aug 17, 2020 at 12:49 comment added joro Thanks again! I might have a bug in my program, trying to debug it and write then.
Aug 16, 2020 at 11:04 comment added Louis D Again, my answer explains that these can’t be counterexamples. All of your examples are subgraphs of the non-Hamiltonian graph $K_{1,1,\dots,1,(n+1)/2}$. In this graph $d_{(n-1)/2}=(n-1)/2$ and $d_{(n+1)/2}=(n-1)/2$ so Nash-Williams doesn’t hold. Since you aren’t providing the degree sequence I can’t tell why you think it does.
Aug 16, 2020 at 5:48 comment added joro Thanks. I had typo in the first graph. According to my computations, the following non-hamiltonian digraphs satisfy nash's hypothesis, would you please verify them: (1, 1, 1, 3, 7) and (1, 1, 1, 2, 2, 8)
Aug 15, 2020 at 22:54 history answered Louis D CC BY-SA 4.0