Timeline for When does a one-dimensional Schrödinger operator have a threshold resonance?
Current License: CC BY-SA 4.0
4 events
| when toggle format | what | by | license | comment | |
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| Aug 14, 2020 at 16:58 | comment | added | Christian Remling | Actually, $L$ need not have continuous spectrum on $(0,\infty)$, the spectrum can be pure point. What is true is that the essential spectrum equals $[0,\infty)$. | |
| Aug 14, 2020 at 15:26 | history | edited | LSpice | CC BY-SA 4.0 |
schrodinger -> Schrödinger
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| Aug 14, 2020 at 15:11 | review | First posts | |||
| Aug 14, 2020 at 15:24 | |||||
| Aug 14, 2020 at 15:06 | history | asked | user | CC BY-SA 4.0 |