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Sep 13, 2010 at 13:07 vote accept Peter Erskin
Aug 28, 2010 at 1:32 comment added Gjergji Zaimi @Qiaochu: Yes, I don't know why I wrote it like that, same thing I guess. @Peter Erskin, I mentioned above that combinatorialists care about the case of infinitely many variables. What reasons do we have to believe that $a_{k,\rho}$ has any nice form? They aren't even integers, and they depend on $N$...
Aug 27, 2010 at 15:54 comment added Qiaochu Yuan @Gjergji: instead of the first identity I would just say that the trace of the matrix you wrote down is p_{k-n} and leave it at that.
Aug 27, 2010 at 15:40 comment added Peter Erskin Thank you very much for the explicit (in contrast to previous suggestions) formula and for the clarification! The formula really works and it looks simpler than the determinant-of-determinants that I proposed in the "Note Added". Unfortunately, I do not see how to present your expression for $ p_k$ in the form similar to your formula for $ e_n $. Is it possible to find the combinatorial coefficients $ a_{k;\rho} $ as discussed in my question?
Aug 27, 2010 at 12:06 history edited Gjergji Zaimi CC BY-SA 2.5
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Aug 27, 2010 at 11:16 history answered Gjergji Zaimi CC BY-SA 2.5