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Aug 9, 2020 at 9:52 history edited Michael Stoll CC BY-SA 4.0
Added link to my paper.
Aug 9, 2020 at 9:47 comment added Michael Stoll This is, in fact, quite usual in this business: many of these results (for small exponents) involve the computation of some Selmer group, which in turn depends on determining class groups (and unit groups) of certain algebraic number fields. Assuming GRH, class groups can be computed in reasonable time for much larger fields (in terms of degree and discriminant) than unconditionally. In the concrete case, what you need is that the class group of $\mathbb Q(\sqrt[p]{2})$ has odd order (and $p$ is not a Wieferich prime).
Aug 9, 2020 at 9:42 vote accept Q_p
Aug 9, 2020 at 9:31 history answered Michael Stoll CC BY-SA 4.0