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Apr 18 at 1:16 vote accept geocalc33
Nov 2, 2022 at 0:18 answer added Caleb Briggs timeline score: 3
Oct 31, 2022 at 20:49 history edited geocalc33 CC BY-SA 4.0
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S Oct 17, 2022 at 17:03 history bounty ended CommunityBot
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S Oct 9, 2022 at 15:25 history bounty started geocalc33
S Oct 9, 2022 at 15:25 history notice added geocalc33 Authoritative reference needed
Feb 11, 2022 at 2:21 history edited geocalc33 CC BY-SA 4.0
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Feb 10, 2022 at 15:49 history edited geocalc33 CC BY-SA 4.0
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Feb 12, 2021 at 0:21 comment added fedja Sure. If you need to know more, just state clearly what you are now interested in and link to what has been done already to give everybody a clear picture of where the things stand. Follow-ups are pretty common on this site.
Feb 11, 2021 at 21:24 comment added geocalc33 @fedja Do you think it would be appropriate to ask a follow up question, about a possible further continuation for Re(z)<0?
Jan 9, 2021 at 3:13 comment added fedja I see nothing wrong with it (though I haven't checked all the statements about fast decay carefully, I'm pretty sure that @metamorphy will supply all details if you request clarification). At least, it is in good agreement with the notes I linked to: the sum of the series is real analytic for $0<s<1$ and extends to the half-plane $\Re z<1$ but it loses the real analyticity property on the line for $s>1$, so no extension from the real line is possible there. My proof promptly breaks down when $s<1$, metamorphy's series promptly diverges for $s>1$, so everything seems to fit together :-)
Jan 6, 2021 at 21:37 comment added fedja @geocalc33 I discussed the problem with Misha Sodin and you can find the result of this discussion in the set of handwritten notes at drive.google.com/file/d/191PhSQzr5Q-MbfuMzmuiogJZrk2bh9Ko/… .It is supposed to show that the sum of the series is not real analytic at any point $s>1$. I hope there is no mistake, but the argument is a bit involved. Maybe I'll post it as a proper answer later. The possibility still remains that you can go through the boundary of the half-plane $\Re z<1$ somewhere far from the real line but it is another story.
S Oct 16, 2020 at 13:01 history bounty ended CommunityBot
S Oct 16, 2020 at 13:01 history notice removed CommunityBot
S Oct 8, 2020 at 11:59 history bounty started geocalc33
S Oct 8, 2020 at 11:59 history notice added geocalc33 Authoritative reference needed
Sep 20, 2020 at 19:01 history edited geocalc33 CC BY-SA 4.0
added the information that there is a partial answer on the original question
Aug 13, 2020 at 7:07 comment added fedja @JohnJiang You are missing the fact that the exponents $n^s$ not only grow in size but also rotate for complex $s$, so the minus sign becomes quite useless and you get arbitrarily huge terms. I suspect that there is no continuation from the real line anywhere though I cannot offer a proof off hand.
Aug 9, 2020 at 6:22 comment added Gerry Myerson I dunno, I just thought it was an important piece of information that should be on record here.
Aug 9, 2020 at 5:00 comment added John Jiang @GerryMyerson Re s > 0 or am I missing something obvious?
Aug 8, 2020 at 23:54 comment added Gerry Myerson To lay the groundwork for this question, in what region of the complex plane does the given series already converge to an analytic function?
Aug 8, 2020 at 16:37 comment added Wojowu Do you have a reason to believe this function odes have an analytic continuation? If so, what do you mean with "what is it"? I really doubt there is an expression for this analytic continuation in terms of more classical functions.
Aug 8, 2020 at 15:34 history edited Stopple CC BY-SA 4.0
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Aug 8, 2020 at 15:17 history asked geocalc33 CC BY-SA 4.0