Timeline for Spectral symmetry of a certain structured matrix
Current License: CC BY-SA 4.0
8 events
| when toggle format | what | by | license | comment | |
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| Aug 5, 2020 at 11:54 | comment | added | vidyarthi | great! a useful trick in evaluating some determinants | |
| Aug 5, 2020 at 11:53 | comment | added | Carlo Beenakker | Since $X^2=1$, you can multiply $\det(\lambda-A)$ with $\det X^2=(\det X)^2$; and since the product of determinants is the determinant of the matrix product, you have $\det(\lambda-A)=\det[X(\lambda-A)X]=\det(\lambda X^2-XAX)$. | |
| Aug 5, 2020 at 11:50 | comment | added | vidyarthi | how did you get $\det(\lambda I-A)=\det(\lambda X^2-XAX)$? | |
| Aug 5, 2020 at 11:50 | history | edited | Carlo Beenakker | CC BY-SA 4.0 |
added 10 characters in body
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| Aug 5, 2020 at 11:47 | vote | accept | Sascha | ||
| Aug 5, 2020 at 11:38 | history | edited | Carlo Beenakker | CC BY-SA 4.0 |
added 75 characters in body
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| Aug 5, 2020 at 11:37 | history | edited | LSpice | CC BY-SA 4.0 |
matri -> matrix
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| Aug 5, 2020 at 11:36 | history | answered | Carlo Beenakker | CC BY-SA 4.0 |