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Timeline for Eigenvalues of product of operators

Current License: CC BY-SA 4.0

4 events
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Aug 5, 2020 at 1:47 comment added Kcafe @Darth Vader Yes indeed
Aug 4, 2020 at 23:46 comment added Darth Vader Are you assuming $A$ is a positive trace class operator? Otherwise $A^{1/2}$ doesn't make sense to me..
Aug 4, 2020 at 6:25 comment added Carlo Beenakker the eigenvalues of $A^{1/2}BA^{1/2}$ are the same those of $AB$.
Aug 4, 2020 at 6:17 history asked Kcafe CC BY-SA 4.0