Skip to main content

Timeline for A question of uniqueness

Current License: CC BY-SA 4.0

10 events
when toggle format what by license comment
Aug 4, 2020 at 15:19 comment added Paul @A.Eremenko I said I can only conclude if $\displaystyle ||u(.,R)||_{L^2]0,\pi[}\to^{R\to\infty} 0$. in the sense: if I assume this hypothesis of more
Aug 4, 2020 at 14:58 comment added Alexandre Eremenko @cerise: your conclusion that $\| u(,.R)\|_2\to 0,\; R\to\infty$ is incorrect: it does not hold in my example. From your assumptions AS STATED it does NOT follow that $u=0$. Look in the literature about "passing to the limit under the integral sign".
Aug 4, 2020 at 14:56 history edited Alexandre Eremenko CC BY-SA 4.0
added 487 characters in body
Aug 4, 2020 at 14:20 vote accept Paul
Aug 4, 2020 at 11:00 comment added Paul conflicting opinions of experts, does not help me.
Aug 4, 2020 at 5:32 comment added Paul @ A.Eremenko I edited to continue my reasoning and didn't add anything as additional assumptions. I noticed that the answer is positive to the question if $\displaystyle ||u(.,R)||_{L^2]0,\pi[}\to^{R\to\infty} 0$
Aug 4, 2020 at 5:26 comment added Alexandre Eremenko @cerise: I do not see how you edited your post, but if you add one of the conditions that I suggested, the counterexample will loose its meaning.
Aug 4, 2020 at 4:55 comment added Paul @ A.Eremenko I think you are right, assumptions are missing, I edited my post. I have not yet understood the construction of a counter example
Aug 4, 2020 at 4:33 history edited Alexandre Eremenko CC BY-SA 4.0
added 59 characters in body
Aug 4, 2020 at 3:13 history answered Alexandre Eremenko CC BY-SA 4.0