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Jun 10, 2023 at 14:31 comment added PW_246 This is impossible since a reflexive frame has the infinite sequence of related points $wRwRwR….$ for each point $w$. Provability Logic (modal logic GL) corresponds to finite, transitive, irreflexive frames. GL interprets $\Box$ as an encoding of a proof in a language that can formulate its own provability predicate. GL is characterized by $\Box (\Box P \to P) \to \Box P$, which takes reflexivity off the table immediately.
Jul 31, 2020 at 18:26 vote accept Andrew Bacon
Jul 31, 2020 at 9:13 answer added Emil Jeřábek timeline score: 10
Jul 31, 2020 at 8:16 comment added Andrew Bacon @AndrejBauer Sorry there was a typo in an earlier version of the question (I wrote "frame" instead of "model"). Does it make sense now: $w\Vdash B$ just means $B$ is true at $w$ in the pointed Kripke model $(W,R,w_0,[[.]])$ ?
Jul 31, 2020 at 7:57 comment added Andrej Bauer What does $w \Vdash B$ stand for? I am reading your question as "Can we have a finite Kripke model $(W, R, w_0)$ such that, for all $A$, $w_0 \Vdash \Box A$ iff $w_0 \Vdash A$?" but I don't think that's what you are asking. (If it is, consider the trival model.)
Jul 31, 2020 at 7:33 history edited Andrew Bacon CC BY-SA 4.0
I said "frame" when I meant "model"!
Jul 31, 2020 at 1:33 history asked Andrew Bacon CC BY-SA 4.0