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Jul 29, 2020 at 21:20 comment added Mateusz Kwaśnicki @WillieWong and Asaf Schachar: Thanks! I edited this into the answer (and also reduced the degree from 6 to 4).
Jul 29, 2020 at 21:19 history edited Mateusz Kwaśnicki CC BY-SA 4.0
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Jul 29, 2020 at 17:11 comment added Willie Wong @AsafShachar: if $f$ is a homogeneous polynomial, it is equal to its taylor polynomial of that degree, and hence if $v = (x_0, y_0)$ up to some numerical constant $d^6f(v,v,\ldots, v)$ is the same as $f(x_0, y_0)$.
Jul 29, 2020 at 16:40 vote accept Asaf Shachar
Jul 29, 2020 at 16:40 comment added Asaf Shachar Thanks. Just one question: Why does the fact that $f$ is a homogeneous polynomial of degree $6$ imply that $d^6f$ is non-degenerate? Can we deduce that without explicitly computing $d^6f$?
Jul 29, 2020 at 15:18 history answered Mateusz Kwaśnicki CC BY-SA 4.0