Timeline for Morphism of Verma modules
Current License: CC BY-SA 4.0
12 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Aug 10, 2020 at 14:42 | vote | accept | KKD | ||
| Aug 10, 2020 at 12:08 | vote | accept | KKD | ||
| Aug 10, 2020 at 12:08 | |||||
| Jul 31, 2020 at 6:19 | vote | accept | KKD | ||
| Aug 10, 2020 at 12:08 | |||||
| Jul 30, 2020 at 22:03 | comment | added | Vít Tuček | @CJS This is generally discouraged on this site as it can lead to Questions and Answers which are hard to parse for people coming late to the party. I've amended my answe but since it's midnight for me, I will leave the rest of the calculations to you. If you do them, please share the result with us. Also, I vaguely remember that the choice of constants in these "diamonds" is dealt with in the original BGG article. | |
| Jul 30, 2020 at 22:00 | history | edited | Vít Tuček | CC BY-SA 4.0 |
part 2
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| Jul 30, 2020 at 21:57 | comment | added | KKD | I added some part to my original question. | |
| Jul 28, 2020 at 18:11 | comment | added | KKD | So after doing the computation it turns out, that $a=2$ and $b=1$ is a solution (and any multiple of (2,1)) | |
| Jul 28, 2020 at 17:47 | comment | added | KKD | Thanks for all these answers. At least I understood what's going on. | |
| Jul 28, 2020 at 17:46 | vote | accept | KKD | ||
| Jul 30, 2020 at 15:32 | |||||
| Jul 28, 2020 at 17:29 | comment | added | Vít Tuček | @CJS Because $x_{\alpha_2} = [x_{\alpha_1}, x_{\alpha_3}].$ In general, it is sufficient to consider only action by elements corresponding to simple roots. Alas, this straightforward strategy of finding $u$ gets unfeasible pretty quickly because dimension of graded-homogeneous components of $U(\mathfrak{n}^-)$ grows very fast. | |
| Jul 28, 2020 at 16:20 | comment | added | KKD | Maybe this questions is dumb, but why you are no considering "$x_{\alpha_2}u=0$" too? | |
| Jul 28, 2020 at 15:30 | history | answered | Vít Tuček | CC BY-SA 4.0 |