Skip to main content
4 events
when toggle format what by license comment
Jul 26, 2020 at 1:25 comment added Gerhard Paseman Ah. So you know about 25*27 and 26*26 already. Gerhard "No More Element Of Surprise" Paseman, 2020.07.25.
Jul 26, 2020 at 1:05 comment added Gerry Myerson @Gerhard, yes, where the trick is finding consecutive powerful numbers. Numbers $n$ such that $n$ and $n+1$ are both powerful are tabulated at oeis.org/A060355
Jul 26, 2020 at 0:36 comment added Gerhard Paseman Also, given powerful numbers m and m+1, we have 4m(m+1) and (2m+1)^2 also powerful. Gerhard "Finally Remembered That Contest Problem" Paseman, 2020.07.25.
Jul 26, 2020 at 0:24 history answered Max Alekseyev CC BY-SA 4.0