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Jul 22, 2020 at 21:39 comment added Willie Wong Note that in dimension 5, things start looking better for $\Upsilon$: the domain is 75 dimensional, while the image is $\binom{5}{2} \binom{5}{3} = 100$ dimensional (we note the image is also antisymmetric in the $d$ and $e$ indices), so we have hope.
Jul 22, 2020 at 21:33 history edited Willie Wong CC BY-SA 4.0
fixed minor typos
Jul 22, 2020 at 21:29 comment added Willie Wong Some people take $R_{ijkl} X^l = [\nabla_i, \nabla_j ]X_k$, some people define it to be the negative. I used in this computation the convention indicated in this comment, you are using the opposite one. So my version of the "Killing identity" is off from yours by a minus sign.
Jul 22, 2020 at 20:32 vote accept Spoilt Milk
Jul 22, 2020 at 17:27 comment added Spoilt Milk Shouldn't the Riemann tensor terms be $R_{splm} + R_{smpl} + R_{slpm}$ so that using $R_{s[plm]} = 0$ would give the result mentioned? You have mentioned that your sign convention is different, but I don't get it. Could you please clarify this. Thanks for the answer.
Jul 22, 2020 at 15:45 history edited Willie Wong CC BY-SA 4.0
added 283 characters in body
Jul 22, 2020 at 15:40 history answered Willie Wong CC BY-SA 4.0