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Aug 24, 2010 at 19:02 comment added Joel I've thought of this and it doesn't help me answer the second part of the question; This is because $v_L(Log(1+\pi_L^j))$ is difficult to deduce if $v_L(\pi_L^j) = v_L(1-r)$ for some $r\in\mu_{p^\infty}.$ (in all other cases this value can be calculated using the newton copolygon). This makes finding gererators for Log(1+m_K) hard for an arbitary extension L.
Aug 24, 2010 at 18:41 history answered David Corwin CC BY-SA 2.5