Timeline for Subtle counterexample to $m\neq n$ but $R^m=R^n$ for some ring $R$ ?
Current License: CC BY-SA 2.5
2 events
| when toggle format | what | by | license | comment | |
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| Aug 24, 2010 at 17:43 | comment | added | Simon Wadsley | Oh. Rereading I see this isn't quite what you ask for. But I'll leave it anyway. | |
| Aug 24, 2010 at 17:42 | history | answered | Simon Wadsley | CC BY-SA 2.5 |