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Jul 15, 2020 at 4:22 comment added Iosif Pinelis @SylvainJULIEN : Yes, $f$ is the Mellin transform of $e^{-2\cdot}$. I am very far from an expert in the Mellin transform, though.
Jul 15, 2020 at 4:19 comment added Iosif Pinelis @BenCrowell : Yes, of course.
Jul 14, 2020 at 23:41 comment added Sylvain JULIEN $f(a)$ is a Mellin transform, right? Is this often used to compute seemingly tricky integrals?
Jul 14, 2020 at 23:11 comment added user21349 Is this the technique referred to as differentiation under the integral sign?
Jul 14, 2020 at 21:18 history edited Iosif Pinelis CC BY-SA 4.0
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Jul 14, 2020 at 21:03 vote accept mathouv
Jul 14, 2020 at 20:53 history edited Iosif Pinelis CC BY-SA 4.0
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Jul 14, 2020 at 20:44 history answered Iosif Pinelis CC BY-SA 4.0