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Jul 16, 2020 at 9:30 comment added Daniel Loughran Yes I finally get it now. I think I was getting confused between the small and big fppf site; now it all makes sense, thanks!
Jul 15, 2020 at 10:20 comment added Angelo There is no such flat map; the special fibers of $Pic_{Q/U} \to U$ are concentrated on proper subvarieties of $U$.
Jul 14, 2020 at 20:32 comment added Daniel Loughran Thanks this makes sense. Still, I'm struggling to come up with a flat map $V \to U$ with $V$ connected such that $Pic_{Q/U}(V) \neq \mathbb{Z}$, since the genetic quartic surface has Picard group $\mathbb{Z}$.
Jul 14, 2020 at 19:56 comment added Angelo Formation of the Picard scheme commutes with base change, so the fibers of $Pic_{Q/U} \to U$ are complicated.
Jul 14, 2020 at 19:43 history asked Daniel Loughran CC BY-SA 4.0