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Aug 16, 2020 at 16:27 answer added LSpice timeline score: 2
Jul 14, 2020 at 11:26 comment added lefuneste @Christ: Thank you very much for this fine answer: +1. Why not transform this comment in a genuine answer?
S Jul 13, 2020 at 18:01 history suggested Aurelio CC BY-SA 4.0
Fixed subscripts for restriction of sections.
Jul 13, 2020 at 16:08 comment added Chris A sufficient condition is that $U$ is affine. Indeed $\mathcal{I}$ fits in a s.e.s. $0\to \mathcal{K}\to \mathcal{O}^n\to \mathcal{I}\to 0$ and $H^1(U,\mathcal{K}) = 0$ for $U$ affine.
Jul 13, 2020 at 15:59 review Suggested edits
S Jul 13, 2020 at 18:01
Jul 13, 2020 at 15:26 review Close votes
Jul 18, 2020 at 15:32
Jul 13, 2020 at 14:20 history asked lefuneste CC BY-SA 4.0