Timeline for Baffling proof using function convexity
Current License: CC BY-SA 4.0
8 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Jul 13, 2020 at 0:40 | vote | accept | icewater | ||
| Jul 12, 2020 at 22:46 | answer | added | LSpice | timeline score: 2 | |
| Jul 12, 2020 at 22:26 | comment | added | LSpice | It's just notation. If you can prove the result in the form in which I've stated it, then you can switch the labels $b$ and $c$ in case they're in the other order. | |
| Jul 12, 2020 at 22:25 | comment | added | icewater | Hi LSpice - thanks for answering - the problem is that this is an argument used in a proof that $b \ge c$, so can't really make that assumption here. I'm seriously thinking this entire argument is a mistake | |
| Jul 12, 2020 at 22:21 | comment | added | LSpice | Since the statement is symmetric in $b$ and $c$, it's probably easier just to assume that $a \ge b \ge c \ge d$ and re-write it as $f(b) - f(a) + f(c) - f(d) \le f'(c)(b - d + c - a)$. | |
| Jul 12, 2020 at 22:16 | history | edited | LSpice | CC BY-SA 4.0 |
Link to paper
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| Jul 12, 2020 at 22:03 | review | First posts | |||
| Jul 13, 2020 at 3:29 | |||||
| Jul 12, 2020 at 21:58 | history | asked | icewater | CC BY-SA 4.0 |