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Jul 16, 2020 at 9:13 comment added nikola karabatic @Tyrone if you write this as an answer I will accept it :)
Jul 15, 2020 at 10:51 comment added nikola karabatic This sounds good, didn't know the computation about the n-dimensional HE
Jul 15, 2020 at 10:09 comment added Tyrone What do you mean by acyclic here? If you don't want to use homology, then just use the computation of $\pi_n$ of the $n$-dimensional Hawaiian Earing (which the the $(n-1)$-fold reduced suspension of the Hawaiian Earing).
Jul 15, 2020 at 9:57 comment added nikola karabatic Or did you intend to argue in another way?
Jul 15, 2020 at 9:57 comment added nikola karabatic Hmm you are right about the homology, but I think this argument uses the suspension iso for reduced suspension and reduced homology implicitely and this does NOT hold for not-well-pointed spaces (since the reduced cone is not acyclic, at least I don't see why it should be).
Jul 15, 2020 at 9:52 comment added Tyrone Enough of the homology of the Hawaiian earing is known and is not the homology of the wedge. In fact $\pi_n$ of the $n$-dimensional Hawaiian earing is known (and it is not even free abelian if I recall).
Jul 15, 2020 at 9:45 comment added nikola karabatic @Tyrone: it is not clear to me whether the map becomes a weak equivalence after suspending further
Jul 14, 2020 at 19:47 comment added Tyrone Doesn't your counterexample in $2$ answer this in the negative if $X,Y$ are not well-pointed?
Jul 9, 2020 at 14:34 history asked nikola karabatic CC BY-SA 4.0