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Jul 8, 2020 at 1:48 answer added R. van Dobben de Bruyn timeline score: 5
Jul 7, 2020 at 17:07 review Close votes
Jul 12, 2020 at 3:01
Jul 7, 2020 at 17:03 comment added Francesco Polizzi @R.vanDobbendeBruyn: in fact no, and I am not claiming that this is a proof of anything. For a counterexample (if exists) we must have either $\alpha+\beta+\gamma$ or $u+v$ invertible in $\mathbb{Z}$, and the other quantity an odd prime number. Moreover, the four quantities $$\alpha u, \quad \alpha v + \beta u, \quad \beta v + \gamma u, \quad \gamma v$$ must be all non-negative.
Jul 7, 2020 at 16:57 comment added R. van Dobben de Bruyn @FrancescoPolizzi: do we know anything about positivity of the factors?
Jul 7, 2020 at 16:26 comment added Francesco Polizzi The sum of the coefficients of $$(\alpha x^2 + \beta x + \gamma)(ux +v)$$ is $$(\alpha+\beta+ \gamma)(u+v).$$
Jul 7, 2020 at 16:08 review First posts
Jul 7, 2020 at 17:40
Jul 7, 2020 at 16:02 history asked 芹沢五郎 CC BY-SA 4.0