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Jul 9, 2020 at 16:50 answer added Emil Jeřábek timeline score: 3
Jul 8, 2020 at 10:06 comment added zeraoulia rafik Thanks for the reference , I will check it
Jul 8, 2020 at 10:04 comment added Kasper Andersen Actually Gupta proves that the number of solutions goes to infinity with $n$, see Hansraj Gupta, The American Mathematical Monthly, Vol. 57, No. 5 (May, 1950), pp. 326-329.
Jul 8, 2020 at 9:34 vote accept zeraoulia rafik
Jul 8, 2020 at 3:17 answer added Gerhard Paseman timeline score: 3
Jul 8, 2020 at 2:00 comment added R. van Dobben de Bruyn Quotes from A055506 and A055487 respectively: "All solutions to $\phi(x) = n!$ are in the interval $[n!,(n+1)!]$", and "According to Tattersall, in 1950 H. Gupta showed that $\phi(x) = n!$ is always solvable". The first gives a bound for fixed $n$, while the latter says that there exists a solution for any $n$. (I do not know arguments backing up either claim.)
Jul 8, 2020 at 0:05 review Close votes
Jul 12, 2020 at 3:01
Jul 7, 2020 at 20:57 history edited LSpice CC BY-SA 4.0
Proofreading; link to paper
Jul 7, 2020 at 19:52 answer added Max Alekseyev timeline score: 8
Jul 7, 2020 at 11:28 comment added Wojowu For any fixed $n$, the number of solutions to $\phi(x)=n!$ is bounded, since $\phi(x)$ tends to infinity. However, this number is probably not bounded independently of $n$.
Jul 7, 2020 at 9:59 history edited zeraoulia rafik CC BY-SA 4.0
edited body
Jul 7, 2020 at 9:36 history asked zeraoulia rafik CC BY-SA 4.0