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Jul 11, 2020 at 23:48 comment added Heisenberg Maybe @MartinHairer can correct me but I think if we were to think of a Hilbert space valued Weiner process, $Qf(\cdot)=\int c(s,\cdot) f(s)ds$, $f\in H$ and $Q\in L(H).$
Jul 11, 2020 at 18:35 comment added user81883 @MartinHairer Usually there is some linear operator $Q$ with finite trace in $C(\mathbb{R})$ so that $W_t-W_s\sim N(0,(t-s)Q)$. What is $Q$ in terms of $c$?
Jul 8, 2020 at 1:15 history bounty ended Heisenberg
Jul 7, 2020 at 19:43 comment added Martin Hairer Edited for clarity.
Jul 7, 2020 at 19:42 history edited Martin Hairer CC BY-SA 4.0
Edited for clarity.
Jul 7, 2020 at 19:22 vote accept Heisenberg
Jul 7, 2020 at 19:22 comment added Heisenberg Thank you this helps a lot. This is probably a very basic questions but I don't fully understand how you interpret $c$. On the left side of the second equation you have $c$ evaluated at two measures and on the right side $c$ is evaluated at to real numbers. Why is this possible?
Jul 6, 2020 at 11:02 history answered Martin Hairer CC BY-SA 4.0