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Jul 8, 2020 at 15:05 vote accept Vasily Ilin
Jul 2, 2020 at 6:53 comment added Dave L Renfro See John M. H. Olmsted, Lebesgue theory on a Boolean algebra, Transactions of the American Mathematical Society 51 #1 (January 1942), pp.164-193 AND Roman Sikorski, The integral in a Boolean algebra, Colloquium Mathematicum 2 #1 (1949), pp. 20-26.
Jul 2, 2020 at 1:08 history edited Dmitri Pavlov CC BY-SA 4.0
deleted 4 characters in body; edited tags
Jul 2, 2020 at 1:05 answer added Dmitri Pavlov timeline score: 4
Jul 2, 2020 at 0:16 comment added kirk sturtz You want to look at Fred Lintons thesis and his paper "Functorial measure theory" in the Irvine Proceedings, Thompson , Washington D.C., !966.
Jul 1, 2020 at 23:16 comment added Vasily Ilin @LSpice, yes, I did not think about what I am trying to integrate. Indeed, we need a function not on sets but on actual elements. YCor, I got confused in definitions. A sigma-algebra is a Z_2-algebra, which is also a Boolean ring, i.e. 2x = 0 and x^2 = x for every element x. Also, the point about countable additivity is good.
Jul 1, 2020 at 23:03 comment added Michael Greinecker @LSpice You can identify a measurable function with the function that maps Borel sets to their preimages. This gives you a ring homomorphism from the Borel sets to the ring of measurable sets and you can build a theory of integration for such homomorphisms.
Jul 1, 2020 at 22:55 comment added YCor You wrote "$\mathbf{Z}_2$-algebra (aka Boolean ring)" but obviously not every $\mathbf{Z}_2$-algebra is a Boolean ring.
Jul 1, 2020 at 22:48 comment added Michael Greinecker Do you want your measure theory to be $\sigma$-additive?
Jul 1, 2020 at 22:41 comment added LSpice What would you be trying to integrate? One integrates functions (which are not elements of the $\sigma$-algebra), not subsets. You could maybe build some formal theory (consider the completion of the group algebra of your ring in some appropriate topology …), but the Stone representation theorem says that any algebra is an algebra of subsets anyway, so it seems like you'd be quite close to doing measure theory while carefully avoiding naming the set.
Jul 1, 2020 at 22:41 history edited LSpice CC BY-SA 4.0
\mathbb{Z_2} -> \mathbb Z_2 (2 shouldn't be bold)
Jul 1, 2020 at 22:19 review First posts
Jul 1, 2020 at 22:34
Jul 1, 2020 at 22:18 history asked Vasily Ilin CC BY-SA 4.0