Timeline for Integrability of Fourier transform of truncated fractional power
Current License: CC BY-SA 4.0
7 events
| when toggle format | what | by | license | comment | |
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| Jun 28, 2020 at 3:42 | comment | added | A beginner mathmatician | @Christian. Ok. I missed that observation. Clearly, for $|x|$ we have decay $|\zeta|^{-2}$ at $\infty.$ But how to prove your statement rigorously? | |
| Jun 27, 2020 at 20:25 | comment | added | Christian Remling | The smoothness of this is better than that of $|x|$, which already has Fourier coefficients $\simeq 1/n^2$, so the answer is yes. | |
| Jun 27, 2020 at 19:25 | history | edited | A beginner mathmatician | CC BY-SA 4.0 |
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| Jun 27, 2020 at 19:00 | comment | added | A beginner mathmatician | @Aleksei. I have edited the question. The edited question is what I meant originally. | |
| Jun 27, 2020 at 19:00 | history | edited | A beginner mathmatician | CC BY-SA 4.0 |
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| Jun 27, 2020 at 18:53 | comment | added | Aleksei Kulikov | If $\hat{f}\in L^1(\mathbb{R})$ then $f\in C(\mathbb{R})$ so the answer is no. But this question is more appropriate for math.stackexchange. | |
| Jun 27, 2020 at 18:48 | history | asked | A beginner mathmatician | CC BY-SA 4.0 |