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S Jun 27, 2020 at 19:08 history suggested Daniele Tampieri CC BY-SA 4.0
Minor Math Jaxing (formula hyperlinking + other minor cares) + minor grammar improvements and formatting
Jun 27, 2020 at 18:42 review Suggested edits
S Jun 27, 2020 at 19:08
Jun 27, 2020 at 16:54 comment added user90189 Your second definition of $L^2_\alpha$ is right. Notice that $|\partial^j(\chi m(tx))|\le\sum_l c_lt^l|\partial^{j-l}\chi\,(\partial^l m)(tx)|\le C\sum_l|\partial^{j-l}\chi||x|^{-l}$ and the $L^2$-norm is uniformly bounded. The symbol $e^{i|\xi|^2}$ doesn't satisfy the hypotheses; furthermore, the $L^p\to L^p$ bound only holds for $p=2$; use examples $e^{i|x|^2}f$ for suitable functions $f$, say $f=1/(1+|x|^2)^\alpha$ for $\alpha<n/2$.
Jun 27, 2020 at 15:34 history edited Learn CC BY-SA 4.0
added 167 characters in body; edited tags
Jun 27, 2020 at 13:40 history asked Learn CC BY-SA 4.0