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S Jul 6, 2020 at 0:05 history bounty ended CommunityBot
S Jul 6, 2020 at 0:05 history notice removed CommunityBot
Jun 28, 2020 at 6:54 comment added Carlo Beenakker For $2\times 2$ matrices the answer is yes: the only constraint on the eigenvalues of $C$ is a constraint on the sum $\gamma_1+\gamma_2=\alpha_1+\alpha_2+\beta_1+\beta_2$; the product $\gamma_1\gamma_2=(\alpha_1+\beta_1)(\alpha_2+\beta_2)+\Delta$, where $\Delta$ can take any value independently of $\alpha_1,\alpha_2,\beta_1,\beta_2$, so the product is unconstrained.
S Jun 27, 2020 at 22:19 history bounty started Dmitrii Korshunov
S Jun 27, 2020 at 22:19 history notice added Dmitrii Korshunov Draw attention
S Jun 25, 2020 at 9:51 history suggested Rodrigo de Azevedo
Added tag.
Jun 25, 2020 at 7:57 review Suggested edits
S Jun 25, 2020 at 9:51
Jun 25, 2020 at 2:35 answer added Michael Renardy timeline score: 6
Jun 25, 2020 at 1:56 history asked Dmitrii Korshunov CC BY-SA 4.0