Timeline for When is a distribution having a finite support actually zero?
Current License: CC BY-SA 4.0
6 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Jun 23, 2020 at 14:22 | vote | accept | T. Le | ||
| Jun 23, 2020 at 11:11 | history | became hot network question | |||
| Jun 23, 2020 at 4:49 | answer | added | Piero D'Ancona | timeline score: 8 | |
| Jun 23, 2020 at 4:49 | comment | added | Daniele Tampieri | I think the answer is no even in higher dimension, since the gradient of any characteristic function $\chi_\Omega$, $\Omega\Subset\Bbb R^n$ as exactly the same properties of $D=d/dx$, i.e. $\nabla \chi_\Omega\subseteq\partial\Omega$ as it is shown in this Q&A. And if you need a single PDE satisfying this property, you can take the divergence of the gradient and form the laplacian of the characteristic function. | |
| Jun 23, 2020 at 3:18 | history | edited | T. Le | CC BY-SA 4.0 |
added 3 characters in body
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| Jun 23, 2020 at 3:09 | history | asked | T. Le | CC BY-SA 4.0 |